To count the number of Palindrome's in a String

Given a String S, count the number of palindrome sub strings in the string. The sub string size starts from 1. i.e., Each individual letters counts as a palindrome.



For Example:
If the given string is "dskjkd", the possible substrings which are palindrome are:

d,s,k,j,k,d,kjk

Hence, the count is 7 (Output) 

Implementation:

#include <iostream>
#include<cstring> //To use strlen() function
#define MAX 100000 //Maximum Range for a char Array
using namespace std;

int main()
{
    /* Array to get the input string & to store it as char array. For Example: "dskjkd" */
    char str[MAX]; 
    /* Waits for user to type input. In our case, str[]="dskjkd" */
    cin>>str;
     
    /* To get the length of the string */
    int len = strlen(str);

    /* Left pointer (l) & right pointer (r) */
    int l,r;

    /* Initialize left pointer to point to first character of char array */
    l = 0;

    /* Initialize right pointer to point to last character of the char array */
    r = len - 1;

    /* To store count of matching characters at both ends */
    int active = 0;

    /* Loop until the left pointer & right pointer crosses / matches each other */
    while( l < r )
    {

     /* a. Check whether first character matches last character
        b. If it doesn't matches, move "l" to second character, &  "r" remains in the same position pointing to last character */
     if(str[l] != str[r])
     {
      l++;
     }

     /* c. If it matches, move "l" to next successive character & "r" to  previous character 
        d. Increment active count */
     else
     {
      l++;
      r--;
      active++;
     }
    }

    /* If there exists at-least a single palindrome with string length as 2, print length of the string + 1, because each character is a palindrome substring + there exists at least one palindrome with length >=2 */
    if(active >= 2)
    {
     int out = len + 1;
     cout<<out;
    }

    /* If it doesn't exists, print the length of the string , because each character in the string is considered as palindrome with length 1*/
    else
    cout<<len;
    return 0;
}